JAMB Mathematics 2017 Paper

Concept:When two graphs intersect, their $y$-values are equal at the same $x$-value.Here, the intersection occurs at $x = 2$.Explanation:At the point of intersection, set the two expressions for $y$ equal.For the second graph, substitute $x = 2$:$y = 2(2)^2 - 1 = 2(4) - 1 = 7$.For the first graph, substitute $x = 2$:$Y = p(2)^2 + q = 4p + q$.Since both graphs pass through the same point at $x = 2$, equate them:$4p + q = 7$.Make $p$ the subject of the formula:$4p = 7 - q$.Divide both sides by $4$:$p = \frac{7 - q}{4}$.This is the required value of $p$ in terms of $q$.Answer:$p = \frac{7 - q}{4}$.