Length of the arc = θ360×2πr\frac{\theta}{360} \times 2\pi r360θ×2πr
= 300360×2×227×14\frac{300}{360} \times 2 \times \frac{22}{7} \times 14360300×2×722×14
= 2203\frac{220}{3}3220
= 73.33 cm
Perimeter of the sector = Length of the arc + 2r
= 73.33 + 2(14)
= 101.33 cm
