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JAMB Mathematics 2018 Paper

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Question : 15

Total: 62

Make T the subject of the relation.

T = $\frac{R + P3}{15Q}$
T = $\frac{R - 15P^3}{Q}$
T =R - $\frac{15P^3}{Q}$
T = $\frac{15R + Q}{P^3}$

Solution:

P = ( $\left(\frac{Q(R-T)}{15}\right)^{\frac{1}{3}}$

take cube of both sides

$P^3 = \frac{Q(R-T)}{15}$

cross multiply

$15P^3 = Q(R-T)$

$\frac{15P^3}{Q}$ = R - T

T = R - $\frac{15P^3}{Q}$

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