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JAMB Mathematics 2018 Paper

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Question : 4

Total: 62

A trader realises 10x - x

^2

Naira profit from the sale of x bags of corn. How many bags will give him the maximum profit?

7
6
5
4

Solution:

Concept:

The maximum profit is found where the derivative of the profit function is zero.

Explanation:

Let the profit be

P(x) = 10x - x^2

for

x

bags.

Differentiate with respect to

x

:

\frac{dP}{dx} = 10 - 2x

Set

\frac{dP}{dx} = 0

for maximum profit:

10 - 2x = 0

2x = 10

x = \frac{10}{2} = 5

Therefore, 5 bags will give the maximum profit.

Answer:

C. 5 bags

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