∫5x\frac{5}{x}x5 dx = 5 ∫1x\frac{1}{x}x1 = 5Inx
Since the integral of 1x\frac{1}{x}x1 is Inx
∫2^{2}2 1_{1}1∫ 5x\frac{5}{x}x5 dx = 5
dx = 5 (In<2 – InIn1)
= 3.4657
= 3.47
