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JAMB Mathematics 2018 Paper

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Question : 54

Total: 62

A box contains two red balls and four blue balls. A ball is drawn at random from the box and then replaced before a second ball is drawn. Find the probability of drawing two red balls.

$\frac{2}{3}$
$\frac{1}{3}$
$\frac{1}{4}$
$\frac{1}{9}$

Solution:

Total number of balls = 2 + 4 = 6

P(of picking a red ball) = $\frac{2}{6}$ = $\frac{1}{3}$

P(of picking a blue ball) = $\frac{4}{6}$ = $\frac{2}{3}$

With replacement,

P( picking two red balls) = $\frac{1}{3}$ × $\frac{1}{3}$ = $\frac{1}{9}$

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