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JAMB Mathematics 2018 Paper

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Question : 7

Total: 62

Solve for t in the equation

\frac{3}{4}

\frac{1}{3}

(21 - t) = 11

$\frac{9}{13}$
$\frac{7}{13}$
5
9 $\frac{3}{5}$

Solution:

$\frac{3}{4}$ t + $\frac{1}{3}$ (21 - t) = 11

Multiply through by the LCM of 4 and 3 which is 12

12 x( $\frac{3}{4}$ t) + 12 x ( $\frac{1}{3}$ (21 - t)) = (11 x 12)

9t + 4(21 - t) = 132

9t + 84 - 4t = 132

5t + 84 = 132

5t = 132 - 84 = 48

t = $\frac{48}{5}$

t = 9 $\frac{3}{5}$

Answer is D

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