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JAMB Mathematics 2019 Paper

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Question : 13

Total: 73

Given matrix M =

\begin{vmatrix} -2 & 0 & 4 \\ 0 & -1 & 6 \\ 5 & 6 & 3 \end{vmatrix}

M^{T} + 2M

$\begin{vmatrix} -4 & 2 & 1 \\ 6 & 0 & 5 \\ 0 & 6 & 2 \end{vmatrix}$
$\begin{vmatrix} -6 & 0 & 13 \\ 0 & -3 & 18 \\ 14 & 18 & 9 \end{vmatrix}$
$\begin{vmatrix} 5 & 2 & 6 \\ 0 & 1 & 1 \\ 3 & 4 & -7 \end{vmatrix}$
$\begin{vmatrix} -4 & 0 & 8 \\ 0 & -2 & -16 \\ 10 & 12 & 6 \end{vmatrix}$

Solution:

M = $\begin{vmatrix} -2 & 0 & 4 \\ 0 & -1 & 6 \\ 5 & 6 & 3 \end{vmatrix}$

M $^{T}$ = $\begin{vmatrix} -2 & 0 & 5 \\ 0 & -1 & 6 \\ 4 & 6 & 3 \end{vmatrix}$

2M = $\begin{vmatrix} -4 & 0 & 8 \\ 0 & -2 & 12 \\ 10 & 12 & 6 \end{vmatrix}$

M $^{T}$ + 2M = $\begin{vmatrix} -6 & 0 & 13 \\ 0 & -3 & 18 \\ 14 & 18 & 9 \end{vmatrix}$

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