4sin2x−3=04\sin^2 x - 3 = 04sin2x−3=0
4sin2x=3 ⟹ sin2x=344\sin^2 x = 3 \implies \sin^2 x = \frac{3}{4}4sin2x=3⟹sin2x=43
sinx=32\sin x = \frac{\sqrt{3}}{2}sinx=23
∴x=sin−1(32)\therefore x = \sin^{-1} \left( \frac{\sqrt{3}}{2} \right)∴x=sin−1(23)
x = 60°
