d/dx [ (4x³ - 2x)] is equal to

Correct Answer is : 12x2−24x3−2x12x² - 2/4x³ - 2x4x3−2x12x2−2

Correct Answer is : 12x2−24x3−2x12x² - 2/4x³ - 2x4x3−2x12x2−2

Test Index

JAMB Mathematics 2019 Paper

Question : 25

Total: 73

\frac{d}{dx} [\log (4x^3 - 2x)]

is equal to

Solution:

$\frac{d}{dx} [\log (4x^3 - 2x)]$ ... (1)

Let u = 4x $^3$ - 2x.

$\frac{d}{dx} (\log (4x^3 - 2x)) = \left(\frac{d}{du}\right)\left(\frac{du}{dx}\right)$

$\frac{d}{du} (\log u)$ = $\frac{1}{u}$

$\frac{du}{dx} = 12x^2 - 2$

$\therefore \frac{d}{dx} [\log (4x^3 - 2x)] = \frac{12x^2 - 2}{u}$

= $\frac{12x^2 - 2}{4x^3 - 2x}$

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