Since A(x, y) is the point of equidistance between B and C, then
AB = AC
(AB)2^22 = (AC)2^22
Using the distance formula,
(x - 0)2^22 + (y - 2)2^22 = (x - 2)2^22 + (y - 1)2^22
x2^22 + y2^22 - 4y + 4 = x2^22 - 4x + 4 + y2^22 - 2y + 1
x2^22 - x2^22 + y2^22 - y2^22 + 4x - 4y + 2y = 5 - 4
4x - 2y = 1
