∫(4x−3−7x2+5x−6)dx\int (4x^{-3} - 7x^2 + 5x - 6) dx∫(4x−3−7x2+5x−6)dx
= 4x−3+1−3+1−7x2+12+1+5x1+11+1−6x\frac{4x^{-3+1}}{-3+1} - \frac{7x^{2+1}}{2+1} + \frac{5x^{1+1}}{1+1} - 6x−3+14x−3+1−2+17x2+1+1+15x1+1−6x
= −2x−2−73x3+52x2−6x-2x^{-2} - \frac{7}{3} x^3 + \frac{5}{2} x^2 - 6x−2x−2−37x3+25x2−6x