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JAMB Mathematics 2020 Paper

Question : 14

Total: 40

^{\circ}

. Calculate the perimeter of the sector.

Solution:

The lenght of Arc AB = $rac{Q}{360}$ 2 $\pi$ r

= $rac{48}{360}$ x 2 $rac{22}{7}$ x 10.5 = $rac{48}{360}$ x 2 $rac{22}{7}$ x $rac{21}{2}$

= $\frac{4 \times 22 \times 3}{30} \times \frac{88}{10}$ = 8.8cm

Perimeter = 8.8 + 2r = 8.8 + 2r

= 8.8 + 2(10.5)

= 8.8 + 21

= 29.8cm

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