JAMB Mathematics 2020 Paper

$\frac{\sqrt{2}}{x + 2}$ = x - $\frac{1}{\sqrt{2}}$

x$\sqrt{2}$ (x - $\sqrt{2}$) = x + $\sqrt{2}$ (cross multiply)

x$\sqrt{2}$ - 2 = x + $\sqrt{2}$

= x$\sqrt{2}$ - x

= 2 + $\sqrt{2}$

x ($\sqrt{2}$ - 1) = 2 + $\sqrt{2}$

= $\frac{2 + \sqrt{2}}{\sqrt{2} - 1} \times \frac{\sqrt{2} + 1}{\sqrt{2} + 1}$

x = $\frac{2\sqrt{2} + 2 + 2 + \sqrt{2}}{2 - 1}$

= 3$\sqrt{2}$ + 4