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JAMB Mathematics 2020 Paper

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Question : 35

Total: 40

Three consecutive terms of a geometric progression are give as n - 2, n and n + 3. Find the common ratio

$\frac{3}{2}$
$\frac{2}{3}$
$\frac{1}{2}$
$\frac{1}{4}$

Solution:

$\frac{h}{n-2} = \frac{n+3}{n}$

n ${}^2$ = (n + 3) (n - 2)

n ${}^2$ = n ${}^2$ + n - 6

n ${}^2$ + n - 6 - n ${}^2$ = 0

n - 6 = 0

n = 6

Common ratio: $\frac{n}{n-2} = \frac{6}{6-2} = \frac{6}{4}$ = $\frac{3}{2}$

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