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JAMB Mathematics 2020 Paper

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Question : 4

Total: 40

Find all real number x which satisfy the inequality

\frac{1}{3}

\frac{1}{5}

(x + 4)

x < 11
x < -1
x > 6
x > 11

Solution:

$\frac{1}{3}$ (x + 1) - 1 > $\frac{1}{5}$ (x + 4) = $\frac{x + 1}{3} - 1$ > $\frac{x + 4}{5}$

$\frac{x + 1}{3} - \frac{x + 4}{5} - 1$ > 0

= $\frac{5x + 5 - 3x - 12}{15}$

2x - 7 > 15

2x > 22 = x > 11

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