Concept:Solve the linear inequality by clearing fractions and isolating x.Explanation:Start with the given inequality:3x+1−1>5x+4Multiply every term by the lowest common denominator, 15:15(3x+1)−15(1)>15(5x+4)Simplify each term:5(x+1)−15>3(x+4)Expand the brackets:5x+5−15>3x+125x−10>3x+12Subtract 3x from both sides:2x−10>12Add 10 to both sides:2x>22Divide both sides by 2:x>11Answer:x>11This corresponds to option D.