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JAMB Mathematics 2021 Paper

Question : 15

Total: 40

\frac{1}{3}

\frac{2}{3}

Solution:

use "T" to represent the total profit. The first receives $\frac{1}{3}$ T

remaining, 1 -

\frac{1}{3}

\frac{2}{3}

The seconds receives the remaining, which is

\frac{2}{3}

also

\frac{2}{3}

\frac{2}{3}

\frac{4}{9}

The third receives the left over, which is

\frac{2}{3}

T -

\frac{4}{9}

T = (

\frac{6-4}{9}

\frac{2}{9}

The third receives

\frac{2}{9}

T which is equivalent to N12000

\frac{2}{9}

T = N12, 000

T =

\frac{12000}{\frac{2}{9}}

= N54, 000

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