Test Index

JAMB Mathematics 2022 Paper

Question : 18

Total: 39

Evaluate Log

_{2}

8√2

Solution:

where Log $_{2}$ 8√2 → Log $_{2}$ √128

→ Log $_{2}$ 128 $^{\frac{1}{2}}$

= $\frac{1}{2}$ * (Log $_{2}$ 128) → $\frac{1}{2}$ * (Log $_{2}$ 2 $^{7}$ )

= 7 * $\frac{1}{2}$ * (Log $_{2}$ 2)

where (Log $_{2}$ 2) = 1

→ 7 * $\frac{1}{2}$ * 1

= $\frac{7}{2}$ or 3.5

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