Let the given points be: P(-3, -14) = (x1, y1) Q(t, -5) = (x2, y2) PQ = 9 units (given) Using the distance formula,
d = √ [ (x2−x1)2+(y2−y1)2]
PQ = √ [ (t−(−3))2+(−5+14)2]
implies √ [ (t+3)2+81] = 9
Squaring on both sides, ⇒ (t + 3)2 + 81 = 81 ⇒ (t + 3)2 = 0 ⇒ t + 3 = 0 ∴ t = -3
