limx→2x2+4x−12x2−2x\lim\limits_{x\to 2} \frac{x^2 + 4x - 12}{x^2 - 2x}x→2limx2−2xx2+4x−12 = limx→2(x−2)(x+6)x(x−2)\lim\limits_{x\to 2} \frac{(x - 2)(x + 6)}{x(x - 2)}x→2limx(x−2)(x−2)(x+6)
limx→2x+6x\lim\limits_{x\to 2} \frac{x + 6}{x}x→2limxx+6
2+62=82\frac{2 + 6}{2} = \frac{8}{2}22+6=28 = 4
