JAMB Mathematics 2023 Paper

Let the total number of items in the man's shop = $y$

Number of Brand A's items in the man's shop = $rac{1}{9} y$

Remaining items = 1 - $\frac{1}{9} y = \frac{8}{9} y$

Number of Brand B's items in The man's shop = $rac{5}{8} \text{ of } \frac{8}{9} y = \frac{5}{9} y$

Total of Brand A and Brand B's items = $rac{1}{9} y + \frac{5}{9} y = \frac{2}{3} y$

Number of Brand C's items in the man's shop = 1 - $rac{2}{3} y = \frac{1}{3} y$

$\Rightarrow \frac{1}{3} y$ = 81 (Given)

$\Rightarrow y$ = 81 x 3 = 243

∴ The total number of items in the man's shop = 243

∴ Number of Brand B's items in the man's shop = $\frac{5}{9}$ x 243 = 135

∴ The number of more Brand B items than Brand C = 135 - 81 =54