Calculate the area of the composite figure above.
Area of the composite figure = Area of semi circle + Area of rectangle + Area of triangle
Area of semi circle = 12πr2=12×π×d24=12×227×4224=693 m2\frac{1}{2}\pi r^2 = \frac{1}{2}\times\pi\times\frac{d^2}{4} = \frac{1}{2}\times\frac{22}{7}\times\frac{42^2}{4} = 693\,\text{m}^221πr2=21×π×4d2=21×722×4422=693m2
Area of rectangle = l x b = 42 x 60 =2520 m2^22
Area of triangle = 12×b×h=12×36×42=756 m2\frac{1}{2}\times b \times h = \frac{1}{2}\times 36 \times 42 = 756\,\text{m}^221×b×h=21×36×42=756m2
∴ Area of the composite figure = 693 + 2520 + 756 = 3969 m2^22
