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JAMB Mathematics 2023 Paper

Question : 69

Total: 80

Solution:

Volume of a cone = $\frac{1}{3}\pi r^{2} h$

r = 5 cm

l = 13 cm

Using Pythagoras theorem

⇒

13^{2} = 5^{2} + h^{2}

⇒

169 = 25 + h^{2}

⇒

169 - 25 = h^{2}

⇒

h^{2} = 144

⇒

h = \sqrt{144} = 12\,\text{cm}

∴ Volume of the cone = $\frac{1}{3} \times \pi \times 5^{2} \times 12 = 100\pi$ cm $^{3}$

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