Speed = DistanceTime
⇒ Time = DistanceTime
Let D = distance between the two airports
∴ Time taken to get to the airport = D120 and Time taken to return =D150
Since total time of flight= 3hours,
⇒ D120+D150 = 3
⇒ 15D+12D1800 = 3
⇒ 27D1800 = 3
⇒ 3D200=31
⇒ 3D = 200 x 3
∴ D =200×33= 200km
