JAMB Mathematics 2023 Paper

On the $y$-axis, each box is $\frac{1-0}{5} = \frac{1}{5}$ = 0.2unit

On the $x$-axis, each box is $\frac{90-0}{6} = \frac{90}{6} = 15^{\circ}$

⇒ $\theta_1 = 180^{\circ} + (2.5 \times 15^{\circ}) = 180^{\circ} + 37.5^{\circ} = 217.5^{\circ} \simeq 218^{\circ}$(2 and half boxes were counted to the right of 180$^{\circ}$)

⇒ $\theta_2 = 270^{\circ} + (3.5 \times 15^{\circ}) = 270^{\circ} + 52.5^{\circ} = 322.5^{\circ} \simeq 323^{\circ}$(3 and half boxes were counted to the right of 270$^{\circ}$)

∴ $\theta = 218^{\circ}, 323^{\circ}$