JAMB Mathematics 2023 Paper

Let $x$ = number of VIP tickets sold and

$y$ = number of regular tickets soldTotal number of tickets sold = 200⇒ $x$ + $y$ = 200 ---- (i)If it costs ₦1,200 for a VIP ticket, then it costs ₦1200x for $x$ number of VIP tickets sold andIf it costs ₦700 for a regular ticket, then it costs ₦700$y$ for $y$ number of VIP tickets soldThe total amount realised from the sale of tickets = ₦180,000⇒ 1200$x$ + 700$y$ = 180000 ----- (ii)From equation (i)$x$ = 200 - $y$ ----- (iii)Substitute (200 - $y$) for $x$ in equation (ii)⇒ 1200(200 - $y$) + 700$y$ = 180000⇒ 240000 - 1200$y$ + 700$y$ = 180000⇒ 240000 - 500$y$ = 180000

Collect like terms

⇒ 240000 - 180000 = 500$y$⇒ 60000 = 500$y$

⇒ $y = \frac{60000}{500} = 120$

Substitute 120 for $y$ in equation (iii)

⇒ $x = 200 - 120$⇒ $x = 80$∴ The total number of VIP tickets sold is 80 and regular is 120