Concept:Solving a linear inequality by expanding brackets and collecting like terms.Explanation:Expand both sides.3(x−1)≤2(x−3)3x−3≤2x−6Subtract 2x from both sides.3x−2x−3≤2x−2x−6x−3≤−6Add 3 to both sides.x−3+3≤−6+3x≤−3Answer:x≤−3This corresponds to option A.