The area of a triangle given two sides and the included angle = 12\;\frac{1}{2}21 x a x b x Sinθ\thetaθ
a = b = 8cm
θ\thetaθ = 60º
Area = 12\;\frac{1}{2}21 x 8 x 8 x Sin 60º = 12\;\frac{1}{2}21 x 64 x 32\;\frac{\sqrt{3}}{2}23 ( Sin 60º = 32\;\frac{\sqrt{3}}{2}23 )
= 6434\;\frac{64\sqrt{3}}{4}4643 = 163cm2\sqrt{3}\mathrm{cm}^23cm2
