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JAMB Mathematics 2024 Paper

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Question : 17

Total: 50

From the top of a building 10m high, the angle of elevation of a fruit on top of a tree 25m is 30º. Calculate the horizontal distance between the building and the tree.

15 $\sqrt{3}$ m
5 $\sqrt{3}$ m
25 $\sqrt{3}$ m
30 $\sqrt{3}$ m

Solution:

From the diagram above:

Tan 30º = $\;\frac{15}{x}$

$\;\frac{\sqrt{3}}{3}$ = $\;\frac{15}{x}$

x $\sqrt{3}$ = 3 x 15 = 45

x = $\;\frac{45\sqrt{3}}{3}$ = 15 $\sqrt{3}$ m ( this is after rationalizing the denominator)

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