y ∝ 1x\frac{1}{x}x1
y = kx\frac{k}{x}xk
y = 4, x = 12\frac{1}{2}21, find x when y = 10
4 = k12\frac{k}{\frac{1}{2}}21k
k = 2
Therefore, x = 210=15\frac{2}{10} = \frac{1}{5}102=51