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JAMB Mathematics 2024 Paper

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Question : 38

Total: 50

A bag contains 7 red and 4 black identical balls. Two balls were picked at random from the bag and replaced each time. Find the probability the two balls were of same colour.

$\frac{54}{121}$
$\frac{65}{121}$
$\frac{29}{55}$
$\frac{27}{55}$

Solution:

Total Balls 7 + 4 = 11

Probability of Picking Two Balls of the Same Colour = RR or BB =

\frac{7}{11} \times \frac{7}{11}

+

\frac{4}{11} \times \frac{4}{11}

= $\frac{49}{121}$ + $\frac{16}{121}$ = $\frac{65}{121}$

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