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JAMB Physics 2010 Paper

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Question : 16

Total: 47

The pressure of one mole of an ideal gas of volume 10-2 m3 at a temperature of 27°c is

[molar gas constant = 8.3 J mol-1 k-1]

2.49 x 10⁴ Nm^-2
2.24 x 10⁴ Nm^-2
2.49 x 10⁵ Nm^-2
2.24 x 10⁵ Nm^-1

Solution:

T = 27 + 273 = 300 K, volume, V = 10-2 m3 molar gass constant, R = 8.3 Jmol- 1k - 1 number of mole, n = 1

PV = NRT

i.e P = (NRT)/V = (1 x 8.3 x 300)/10-2

= 2.49 x 10

^5

Nm

^-2

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