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JAMB Physics 2010 Paper

Question : 6

Total: 47

Solution:

Concept:

Strain energy is the energy stored in a wire when it is stretched elastically.

Explanation:

The extension is the increase in length:

e = 30.5\ \mathrm{cm} - 30.0\ \mathrm{cm} = 0.5\ \mathrm{cm}

Convert to metres:

e = 0.5 \times 10^{-2}\ \mathrm{m} = 0.005\ \mathrm{m}

Strain energy is calculated using the average force times extension:

U = \frac{1}{2} F e

Substitute the values:

U = \frac{1}{2} \times 300\ \mathrm{N} \times 0.005\ \mathrm{m}

Therefore,

U = 150 \times 0.005 = 0.75\ \mathrm{J}

Answer:

0.75\ \mathrm{J}

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