Test Index

JAMB Physics 2014 Paper

Question : 5

Total: 41

Solution:

Concept:

Use the equation of motion that connects initial velocity, acceleration, distance, and final velocity.

Explanation:

The car starts from rest, so initial velocity

u = 0

Acceleration is

a = 3\, \mathrm{m\,s^{-2}}

Distance travelled is

s = 24\, \mathrm{m}

Apply the kinematic equation:

v^{2} = u^{2} + 2as

Substitute the values:

v^{2} = 0^{2} + 2(3)(24)

v^{2} = 144

Take the square root:

v = \sqrt{144} = 12\, \mathrm{m\,s^{-1}}

Answer:

The final velocity is

12\, \mathrm{m\,s^{-1}}

, which is option A.

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