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JAMB Physics 2017 Paper

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Question : 5

Total: 49

Calculate the upthrust on an object of volume 50cm3 which is immersed in liquid of density

10^{3}

kgm-3 [g = 10ms-2]

0.8N
2.5N
0.5N
1.0N

Solution:

Upthrust = change in weight

density =

\frac{\text{mass}}{\text{volume}}

Mass of liquid displaced = Density of Liquid × Volume;

=

10^{3} \times 50 \times 10^{-6}\,\text{m}^{3}

= 0.05kg

(Note that the volume of

50\,\text{cm}^{3}

was converted to

\text{m}^{3}

by multiplying by

10^{6}

) i.e

50\,\text{cm}^{3} = 50 \times 10^{-6}\,\text{m}^{3}

Since mass displaced = 0.05kg

Upthrust = mg = 0.05 × 10

= 0.5N

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