From the law of conservation of linear momentum,
m1u1+m2u2=m1v1+m2v2
Since the collision is inelastic, we have
(0.05×200)−(0.95×0)=(0.05+0.95)V
10=V
V=10ms−1
Hence the Kinetic energy = 12(0.05+0.95)×102
= 12×100
= 50J
