Test Index

JAMB Physics 2018 Paper

Question : 58

Total: 87

\frac{1}{3}

Solution:

Volume of liquid displaced

= $\frac{2}{3}$ (0.5) $^{3}$ = 0.0833cm3

Mass of liquid displaced = mass of floating cube = 75kg

Density of liquid = $\frac{\text{mass}}{\text{volume}}$

= $\frac{75}{0.0833}$

= 900kgm $^{-3}$

R.D of liquid = $\frac{900}{1000}$

= 0.9

Go to Question:

Prev Question

Next Question