Water 1 => M = 150g = 0.15kg,
θ2 = 60oC; θ1 = θ
Q1 = MC (θ2 – θ1)
= 0.15C (60 - θ)
Water 2 => M = 300g = 0.3kg
θ1 = 20oC, θ2 = θ
Q2 = MC (θ2 – θ1)
= 0.3C (θ – 20)
Combining Q1 and Q2
0.15C (60 - θ) = 0.3C (θ – 20)
9 – 0.15θ = 0.3θ – 6
0.3θ + 0.15θ = 9 + 6
0.45 θ = 15
θ = 33.33oC
