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JAMB Physics 2019 Paper
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© africaexams.com
Question : 100
Total: 100
A mass of 0.5kg is whirled in a vertical circle of radius 2m at a steady rate of 2 rev/s. Calculate the centripetal force
164N
160N
158N
172N
Validate
Solution:
ω = 2πF = 2π × 2 = 4πrad
−
1
^{-1}
−
1
Centripetal force = mrω
2
^2
2
⇒ 0.5 × 2 × (4π)
2
^2
2
⇒ 157.75N
Approximately = 158N.
© africaexams.com
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