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JAMB Physics 2019 Paper
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© africaexams.com
Question : 78
Total: 100
The length of the seconds hand of laboratory clock is 0.1m. Calculate the speed at the top of the seconds hand
1.05 × 10
−
2
^{-2}
−
2
ms
−
1
^{-1}
−
1
1.85 × 10
−
4
^{-4}
−
4
ms
−
1
^{-1}
−
1
9.50 × 10
−
1
^{-1}
−
1
ms
−
1
^{-1}
−
1
5.25 × 10
−
3
^{-3}
−
3
ms
−
1
^{-1}
−
1
Validate
Solution:
Length of the seconds hand = r = 0.1m but the seconds hand rotates through 360° or 2π rad in 60s.
Thus,
ω
=
θ
=
2π
60
Velocity of the tip of the hand, V = ωr
V
=
2π
60
×
0.1
=
2π
600
=
π
300
=
3.142
300
V = 0.01047 = 1.05 × 10
−
2
^{-2}
−
2
ms
−
1
^{-1}
−
1
© africaexams.com
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