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JAMB Physics 2020 Paper

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Question : 34

Total: 38

In the figure, the value of R is

3 $\Omega$
6 $\Omega$
4 $\Omega$
5 $\Omega$

Solution:

R $_{T}$ = $\frac{V}{1} = \frac{12}{2}$ = 6 $\Omega$

R $_{T}$ = 3 + $\frac{R \times 6}{R + 6}$

R = 6 $\Omega$

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