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JAMB Physics 2020 Paper

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Question : 4

Total: 38

If in a simple pendulum experiment the length of the inextensible string is increased by a factor of four, its period is increased by a factor of?

4
$\frac{\pi}{2}$
$\frac{1}{4}$
2

Solution:

Concept:

The period of a simple pendulum depends on the square root of its length.

Explanation:

The period is given by

T = 2\pi\sqrt{\frac{L}{g}}

.

So,

T

is proportional to

\sqrt{L}

.

Let the original length be

L_1

and the original period be

T_1

.

The new length is

L_2 = 4L_1

.

Therefore,

\frac{T_2}{T_1} = \sqrt{\frac{L_2}{L_1}} = \sqrt{\frac{4L_1}{L_1}} = \sqrt{4} = 2

.

Thus,

T_2 = 2T_1

.

Answer:

D. 2

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