In a simple pendulum, T = 2π\piπLg\sqrt{\frac{L}{g}}gL
T1T2=L1L2\frac{T_1}{T_2} = \sqrt{\frac{L_1}{L_2}}T2T1=L2L1 but L2_{2}2 = 4L1_{1}1
T1T2=L14L1\frac{T_1}{T_2} = \sqrt{\frac{L_1}{4L_1}}T2T1=4L1L1
T2_{2}2 = 2T1_{1}1