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JAMB Physics 2021 Paper

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Question : 4

Total: 40

A ball of mass 0.5kg moving at 10ms

^{-1}

collides with another ball of equal mass at rest. If the two balls move off together after the impact, calculate their common velocity.

0.2ms $^{-1}$
0.5ms $^{-1}$
5.0ms $^{-1}$
5.5ms $^{-1}$

Solution:

Concept:

In an inelastic collision where the two bodies stick together, the total momentum before impact equals the total momentum after impact.

Explanation:

Let the common velocity after impact be

v

.

Using conservation of momentum:

m_1 u_1 + m_2 u_2 = (m_1 + m_2) v

Here,

m_1 = 0.5 \, \text{kg}

,

u_1 = 10 \, \text{m/s}

,

m_2 = 0.5 \, \text{kg}

,

u_2 = 0

.

Substitute the values:

(0.5 \times 10) + (0.5 \times 0) = (0.5 + 0.5) v

5 + 0 = 1 \times v

Therefore,

v = 5.0 \, \text{m/s}

.

Answer:

C.

5.0 \, \text{m/s}

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