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JAMB Physics 2022 Paper

Question : 7

Total: 40

Solution:

Concept:

The car starts from rest, so the initial velocity is

u = 0

Use the equation of motion

s = ut + \frac{1}{2}at^{2}

to find the acceleration.

Explanation:

Given: distance

s = 40 \, \mathrm{m}

, time

t = 10 \, \mathrm{s}

, and initial velocity

u = 0

Substitute the known values into the equation:

40 = 0 \times 10 + \frac{1}{2} a (10)^{2}

This simplifies to:

40 = 50a

Solve for

a

a = \frac{40}{50} = 0.8 \, \mathrm{m\,s}^{-2}

Therefore, the magnitude of the acceleration is

0.80 \, \mathrm{m\,s}^{-2}

Answer:

0.80 \, \mathrm{m\,s}^{-2}

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