Africa Exams
Where Preparation Meets Success
Home
Botswana
Botswana PSLE Papers
Botswana JCE Papers
Botswana BGCSE Papers
Ghana
Ghana BECE Exams
Kenya
Kenya KCPE Papers
Kenya KCSE Papers
Kenya KASNEB Papers
Nigeria
WAEC Exams
JAMB Exams
Rwanda
Rwanda Primary Papers
Rwanda Secondary Papers
Uganda
Uganda PLE Papers
Uganda UCE Papers
Uganda UACE Papers
Certifications
Technical
Cloud Tech Certifications
Security Tech Certifications
Management
IT Infrastructure
More
About
Contact Us
Our Apps
Privacy
+
-
Test Index
JAMB Physics 2023 Paper
Show Para
Hide Para
Share question:
© africaexams.com
Question : 17
Total: 65
A man swung an object of mass 2 kg in a circular path with a rope 1.2 m long. If the object was swung at 120 rev/min, find the tension in the rope.
400
288
240
379
Validate
Solution:
m=2kg, r=1.2m, f=120rev/min ; T=?
f=
120
r
e
v
1
m
i
n
\frac{120\,\mathrm{rev}}{1\,\mathrm{min}}
1
min
120
rev
×
1
m
i
n
60
s
\frac{1\,\mathrm{min}}{60\,\mathrm{s}}
60
s
1
min
= 2rev\s
w=2
πf= 2×π×2= 4πrad\s
T=
m
v
2
r
\frac{mv^2}{r}
r
m
v
2
, but v = wr
⇒ T =
(
m
)
(
w
r
)
2
r
\frac{(m)(wr)^2}{r}
r
(
m
)
(
w
r
)
2
⇒ T =
m
w
2
r
mw^2r
m
w
2
r
= T = 2× (4
π)^2 × 1.2
T = 379N ( to 3 s.f)
© africaexams.com
Go to Question:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
Prev Question
Next Question
