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JAMB Physics 2023 Paper

Question : 26

Total: 65

Three forces with magnitudes 16 N, 12 N and 21 N are shown in the diagram below. Determine the magnitude of their resultant force and angle with the x-axis

7.63N,61°
8.71N,61°
7.63N,29°
8.71N,29°

Validate

Solution:

Fx= 12cos32°-16cos26° = -4.20N (right is taken +ve and left is taken -ve)

Fy=12sin32°+16sin26°-21 = -7.63N (up is taken +ve and down is taken -ve)

R^2

= 4.202+7.632

⇒

R^2

= 75.86

⇒ R=√75.86

∴R = 8.71 N

tan θ=

\frac{opp}{adj}

⇒tan θ=

\frac{7.63}{4.20}

⇒tan θ =1.8095

⇒ θ =

\tan^{-1}

(1.8095)

θ = 61°

∴The angle of the resultant force with the x-axis is 61°

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