Test Index

JAMB Physics 2023 Paper

Question : 4

Total: 65

[Take g = 10 ms-2]

Solution:

Concept:

Projectile motion range depends on launch speed, angle, and gravity, using the range formula for a symmetric trajectory.

Explanation:

Given values:

u = 75\ \mathrm{ms}^{-1}

\theta = 22^\circ

, and

g = 10\ \mathrm{ms}^{-2}

The horizontal range is given by:

R = \frac{u^2 \sin 2\theta}{g}

Substitute the known values:

R = \frac{75^2 \times \sin 2(22^\circ)}{10}

This simplifies to:

R = \frac{5625 \times \sin 44^\circ}{10}

Since

\sin 44^\circ \approx 0.6947

R = \frac{5625 \times 0.6947}{10}

R = \frac{3907.69}{10} \approx 390.8\ \mathrm{m}

So the horizontal range achieved by the missile is approximately

391\ \mathrm{m}

Answer:

391\ \mathrm{m}

Go to Question:

Prev Question

Next Question