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JAMB Physics 2023 Paper

Question : 43

Total: 65

A charge of

4.6 \times 10^{-5}

3.2 \times 10^{4}

\mathrm{Vm}^{-1}

. What is the force acting on the electron?

Solution:

Concept:

The electric force on a charge in a uniform field is the product of the charge and the electric field intensity:

F = qE

Explanation:

Given charge,

q = 4.6 \times 10^{-5}\ \mathrm{C}

Electric field intensity,

E = 3.2 \times 10^{4}\ \mathrm{Vm}^{-1}

Using

F = qE

, substitute the values:

F = (4.6 \times 10^{-5})(3.2 \times 10^{4})

Multiply the coefficients:

4.6 \times 3.2 = 14.72

Combine the powers of ten:

10^{-5} \times 10^{4} = 10^{-1}

So,

F = 14.72 \times 10^{-1} = 1.472\ \mathrm{N}

Rounding to one decimal place,

F \approx 1.5\ \mathrm{N}

Answer:

The force acting is

1.5\ \mathrm{N}

Correct option: A.

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