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JAMB Physics 2024 Paper

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Question : 110

Total: 125

Two points on a velocity-time graph have coordinates (2s, 5m/s) and (4s, 15m/s). Calculate the mean acceleration

5.0ms $^2$
0.83ms $^2$
1.5ms $^2$
2.0ms $^2$

Solution:

Mean acceleration = $\;\frac{\Delta V}{\Delta t}$

Point 1: (2s, 5m/s)

Point 2: (4s,15m/s)

Mean acceleration = $\;\frac{15 - 5}{4 - 2}$ = 5.0ms $^2$

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