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JAMB Physics 2024 Paper

Question : 24

Total: 125

Solution:

Concept:

For a sonometer wire, the fundamental frequency is directly proportional to the square root of the tension.

Explanation:

The relationship is

f \propto \sqrt{T}

, so

f = k\sqrt{T}

, where

k

is a constant.

Given original frequency:

f_1 = 50\text{ Hz}

at tension

T_1 = T

New tension:

T_2 = 4T

Since

f \propto \sqrt{T}

, doubling the square root means frequency doubles.

Thus,

f_2 = f_1 \times \sqrt{\frac{T_2}{T_1}}

Substitute values:

f_2 = 50 \times \sqrt{\frac{4T}{T}} = 50 \times 2 = 100\text{ Hz}

Answer:

100\text{ Hz}

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